Finding equal potential points in electric circuits

Click For Summary
SUMMARY

This discussion focuses on understanding symmetry in electric circuits to identify equal potential points. The cubic circuit example illustrates that points I, M, and B, H are at equal potential due to their symmetrical connections to voltage sources and resistors R1 and R2. The analysis confirms that points can be grouped based on their connections, leading to simplifications in circuit analysis. The key takeaway is that symmetry allows for the identification of equivalent nodes, which is crucial for calculating equivalent resistance in complex circuits.

PREREQUISITES
  • Understanding of electric circuits and components, including resistors and voltage sources.
  • Familiarity with circuit analysis techniques, particularly symmetry in circuits.
  • Knowledge of equivalent resistance calculations in series and parallel configurations.
  • Basic principles of electrical potential and Kirchhoff's laws.
NEXT STEPS
  • Study the concept of symmetry in electric circuits and its applications in circuit simplification.
  • Learn about Kirchhoff's Voltage Law (KVL) and its role in analyzing potential differences in circuits.
  • Explore advanced circuit analysis techniques, such as Thevenin's and Norton's theorems.
  • Review literature on equivalent resistance calculations in complex circuit configurations.
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing or simplifying electric circuits will benefit from this discussion.

anachin6000
Messages
50
Reaction score
3
Hi! I have a real problem in understanding the use of symmetry for finding equal potential points in nasty electric circuits. There are lots of problems were the solution simply says: "due to symmetry reasons, nodes X and Y have equal potential", but I rarely really understand the so called symmetry. So far I haven't found someone to properly explain to me how this really works.

To better explain myself, I annexed a cubic circuit. The problem asks to find the equivalent resistance when the circuit is connected to a voltage source between points S and A. The values for R1 and R2 are considered known. The solution says that the points I, M and the points H, B are at equal potential, so you can connect them together. Why those points?
Bare in mind, this is no homework, just an example (though I would be grateful if anyone would help me understand it).

So, can anyone explain me how to find symmetry in similar cases or suggest a paper on this topic?
 

Attachments

  • Screenshot (64).png
    Screenshot (64).png
    22.4 KB · Views: 670
Physics news on Phys.org
You can quickly find candidates just by looking at the vertices, checking them is more work:
Are there vertices with 3 R1? T and A, but as the voltage source is connected to A those are not at the same potential.
Are there vertices with 2 R1 and 1 R2? I, M, B, H. Both I and M are connected to S via R2, both B and H are connected to A via R1. Possible candidates.
Are there vertices with 1 R2 and 2 R2? No.
Are there vertices with 3 R2? C and S. Same argument as with T and A: not at the same potential.

Can I/M and B/H be pairs at the same potential?
I is connected to S via R2, to T via R1, to H via R1.
M is connected to S via R2, to T via R1, to B via R1. They are at the same potential if B and H are at the same potential.
The same analysis for B/H shows that they are at the same potential if I and M are at the same potential. In other words, the points are symmetric, and at the same potential within the pairs.
 
  • Like
Likes   Reactions: anachin6000
mfb said:
You can quickly find candidates just by looking at the vertices, checking them is more work:
Are there vertices with 3 R1? T and A, but as the voltage source is connected to A those are not at the same potential.
Are there vertices with 2 R1 and 1 R2? I, M, B, H. Both I and M are connected to S via R2, both B and H are connected to A via R1. Possible candidates.
Are there vertices with 1 R2 and 2 R2? No.
Are there vertices with 3 R2? C and S. Same argument as with T and A: not at the same potential.

Can I/M and B/H be pairs at the same potential?
I is connected to S via R2, to T via R1, to H via R1.
M is connected to S via R2, to T via R1, to B via R1. They are at the same potential if B and H are at the same potential.
The same analysis for B/H shows that they are at the same potential if I and M are at the same potential. In other words, the points are symmetric, and at the same potential within the pairs.
Thank you!This was really helpful and revealing.
 
  • Like
Likes   Reactions: mfb

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 21 ·
Replies
21
Views
4K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 14 ·
Replies
14
Views
6K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 16 ·
Replies
16
Views
4K
  • · Replies 7 ·
Replies
7
Views
3K