May 18, 2008 #1 gtfitzpatrick Messages 372 Reaction score 0 Homework Statement if 0<\lambda<1 and f(x) = x for 0\leqx\leq\lambda\pi and f(x) = (\lambda/1-\lambda)(\pi-\lambda) for \lambda\pi\leqx\leq\pi
Homework Statement if 0<\lambda<1 and f(x) = x for 0\leqx\leq\lambda\pi and f(x) = (\lambda/1-\lambda)(\pi-\lambda) for \lambda\pi\leqx\leq\pi
May 18, 2008 #2 gtfitzpatrick Messages 372 Reaction score 0 show f(x)=2/\pi(1-\lambda) \sum (sinn\lambda\pisinnx)/n^{2}
May 18, 2008 #3 gtfitzpatrick Messages 372 Reaction score 0 so am i right a_{0} and a_{n} are both 0 so then is b_{n} = 1/\pi \int^{\lambda\pi}_{0} xsin(n\pix/\pi) + 1/\pi \int ^{\pi}_{\lambda\pi} ---- sin(n\pix/\pi)
so am i right a_{0} and a_{n} are both 0 so then is b_{n} = 1/\pi \int^{\lambda\pi}_{0} xsin(n\pix/\pi) + 1/\pi \int ^{\pi}_{\lambda\pi} ---- sin(n\pix/\pi)
May 18, 2008 #4 Defennder Homework Helper Messages 2,590 Reaction score 5 I'm not sure what you're writing here, is it \lambda \pi or \lambda^{\pi} ?
May 19, 2008 #5 gtfitzpatrick Messages 372 Reaction score 0 its (\lambda)(\pi) not powered or anything, all on the same line but came out funny sometimes, phi seem to move up a bit
its (\lambda)(\pi) not powered or anything, all on the same line but came out funny sometimes, phi seem to move up a bit
May 19, 2008 #6 Vid Messages 401 Reaction score 0 Use itex instead of tex if you want math symbols to look right in the middle of a line of text.
May 26, 2008 #7 gtfitzpatrick Messages 372 Reaction score 0 so am i right a_{o} and a_{n} are both 0 so then is b_{n} = 1/\pi \int^{\lambda\pi}_{0} xsin(n\pix/\pi) + 1/\pi \int^{pi}_{\lambda\pi} (\lambda/1-\lambda)(\pi-x) sin(n\pix/\pi) do i work from here?
so am i right a_{o} and a_{n} are both 0 so then is b_{n} = 1/\pi \int^{\lambda\pi}_{0} xsin(n\pix/\pi) + 1/\pi \int^{pi}_{\lambda\pi} (\lambda/1-\lambda)(\pi-x) sin(n\pix/\pi) do i work from here?