Finding final image through a lens

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SUMMARY

The discussion focuses on determining the final image location when light is reflected by a mirror and refracted through a lens. The key equations used are the mirror formula (1/s + 1/s' = 2/R) and the lens formula (na/s + nb/s' = (nb-na)/R). The final image is calculated to be located at R/4 to the right of point V, confirming the calculations provided by the participants. The discussion emphasizes the importance of correctly applying the equations to find the image position in optical systems.

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Homework Statement



An object is situated at various points relative to V. The light is then reflected by the mirror, and the final image is viewed by the observer.

http://www.flickr.com/photos/55153239@N03/6196518731/

Homework Equations



1/s + 1/s' = 2/R
na/s + nb/s' = (nb-na)/R

The Attempt at a Solution



The final statement of the problem confused me. It says the final image is viewed from the left of the figure. Therefore, you the mirror create an image inside the lens, and the light would then be refracted to the viewer outside the lens?

for d) I used the second equation to refract the light into the lens, to get s' = -3/2 R. This then acts as the object for the mirror a distance 5/2 R. Using the first equation, i get s' = 5/8 R. This would act as the object for the second refraction outside the lens. the end result is R/4 to the right of V. Is that correct?
 
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Hi coltin.walsh, welcome to PF.
"This would act as the object for the second refraction outside the lens. the end result is R/4 to the right of V."
Check this last step. Show your calculation.
 
so i would have s = 3/8 R. and using the second equation:

1.5/(3R/8) + 1/s' = 0
s' = -R/4
image is located a distance R/4 to the right of V.
 
Last edited:

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