Finding Final Velocity of Mass 1 After Collision

AI Thread Summary
The discussion revolves around calculating the final velocity of mass 1 after a collision with mass 2, using conservation of momentum and kinetic energy principles. The initial conditions include mass 1 moving with a velocity of (1i - 1j) and mass 2 at rest, while after the collision, mass 2 moves with a velocity of (2i - 3j). Participants clarify that while momentum is conserved, kinetic energy is not necessarily conserved in inelastic collisions, which is relevant to this scenario. The calculations presented by the user indicate confusion regarding the application of kinetic energy equations, but it is emphasized that momentum conservation is sufficient for determining the final velocities. The discussion concludes with the understanding that the loss of kinetic energy does not imply the objects stick together post-collision.
Nicki
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Homework Statement


Mass 1 (2.77 kg) moves with an initial velocity (1i - 1j) and mass 2 (1 kg) starts at rest. After the collision, M2 moves with a velocity of (2i - 3j). What is the final velocity of m1?

Homework Equations


Since they don't stick together, KE and linear momentum are conserved.
M1V1ix + M2V2ix = M1V1fx + M2V2fx

M1V1iy + M2V2iy = M1V1fy + M2V2fy

1/2 M1V1i^2 + 1/2M2V2i^2 = 1/2 M1V1f^2 + 1/2M2V2f^2

V1f = (sqrt)V1xf^2 + V1yf^2

The Attempt at a Solution


I don't really understand these problems, and we had a substitute professor into teach this, so here goes nothing, literally.
2.77 (1) + 0 = 2.77 Vx + 1(2) Vx = 0.278 m/s ?
2.77(-1) + 0 = 2.77 Vy + 1(-3) Vy = 0.0.83 m/s ?

This doesn't seem right? Shouldn't I need to use th equations for KE for an elastic collision?
 
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Nicki said:
Since they don't stick together, KE and linear momentum are conserved.
No. Momentum is conserved, but loss of some KE does not necessarily mean the objects coalesce. That is only the extreme case, in which the KE lost is maximised.
 
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