Finding flux through surface where E field is function of x

AI Thread Summary
The discussion revolves around calculating the electric flux through a square in the xy-plane due to an electric field defined as E = (663 N/(C*m))x. The integral for flux is set up as ΦE = ∫Ecos∅dA, simplifying to ΦE = ∫EdA since the electric field and area vector are parallel. The confusion arises regarding the presence of a y factor in the final answer, which is clarified by recognizing that the area element dA is expressed as dx*dy, leading to two integrals: one with respect to y and another for the x-dependent term. Ultimately, the integration confirms that the y factor is necessary due to the area calculation. The discussion concludes with a resolution of the misunderstanding regarding the direction of the electric field.
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Homework Statement


In a region of space there is an electric field E(vector E) that is in the x-direction and that has magnitude E=(663 N/(C*m))x

Find flux for this field through a square in xy plane at z=0 and with side length 0.330m . One side of the square is along the +x-axis and another side is along the +y-axis.

I understand setting up the integral but I do not understand why there is a y in the answer

Homework Equations

The Attempt at a Solution


ΦE= ∫Ecos∅dA , where phi is the angle between the normal area vector and the E field. In this case E-field and A are parallel so cos∅=1 . Thus integral reduces to ΦE=∫EdA. dA of a small piece of the square is determined by dy*dx.

Then, integral becomes ∫663x*dydx (from 0 to 0.330)

Final answer should be

(y*663x^2)/2 (from 0 to 0.330) so final answer is 11.91.

I understand anti derivative of x is x^2/2 but I am not understanding/seeing where the y factor comes from.

Thanks [/B]
 
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You have to integrate with respect to y first. Since the term 663x does not depend on y, you can pull it out, and you have to deal with \int \ dy, which is...?
 
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Hi,

ok so bc A=dxdy and that's part of the integral and like you said 663x does not depend on y you have 2 integrals ∫dy=y and ∫663x= 663*(x^2)/2 (from 0 to 0.330). Ok got it. Thank you for the clarification
 
Jen2114 said:

Homework Statement


In a region of space there is an electric field E(vector E) that is in the x-direction and that has magnitude E=(663 N/(C*m))x

Find flux for this field through a square in xy plane at z=0 and with side length 0.330m . One side of the square is along the +x-axis and another side is along the +y-axis.

I understand setting up the integral but I do not understand why there is a y in the answer
You sure the problem doesn't say the E field is in the z direction?
 
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rude man said:
You sure the problem doesn't say the E field is in the z direction?
Hello, yes I am sorry the problem statement is in z-direction and I solved it with the z-direction in mind but I failed to revise my problem statement submission here. thanks for pointing that out
 
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