Finding Force and Steep Grade for a Train with Given Acceleration and Drag Force

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The discussion revolves around calculating the force exerted by a locomotive on a 25-car train, each car weighing 6.8e4 kg, while considering a drag force of 250v at a speed of 44 km/h and an acceleration of 0.20 m/s². The key equation used is F - drag force = ma, where F is the force exerted by the locomotive. Participants clarify that the total mass of the train is the sum of all cars, and the drag force must also be multiplied by the number of cars. There is confusion regarding whether to consider the force on one car or the entire train, with emphasis on using the total mass for calculations. The thread highlights the need to account for both the mass of the train and the total drag force when determining the locomotive's exerted force.
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Homework Statement


A locomotive accelerates a 25-car train along a level track. Each car has a mass of 6.8e104 kg and is suject to a drag force f = 250v, where v is the speed in m/s and the force f is in N. At the instant when the speed of the train is 44 km/h, the acceleration is 0.20 m/s2.

(a) What is the force exerted by the locomotive on the first car?

(b) Suppose that the force found in part (a) is the greatest force the locomotive can exert of the train. What, then, is the steepest grade up which the locomotive can pull the train at 44 km/h?


Homework Equations



f=ma

The Attempt at a Solution



no attempt; no idea how to approach problem.
 
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chenying said:

Homework Statement


A locomotive accelerates a 25-car train along a level track. Each car has a mass of 6.8e104 kg and is suject to a drag force f = 250v, where v is the speed in m/s and the force f is in N. At the instant when the speed of the train is 44 km/h, the acceleration is 0.20 m/s2.

(a) What is the force exerted by the locomotive on the first car?


Okay. So ma is the resultant force on the train.

Force exerted by train (F) - friction (250v) = Resultant force


Now read the part in bold and see if you can't find F


EDIT: for the second part, they are asking for an angle θ for which the train can produce a constant velocity of 44km/h. Draw the train on an inclined plane at an angle θ. Don't forget to take the weight of train into account.
 
Last edited:
ok, but I am confused with whether the force of the train is equal to the force of the train on one car?
 
chenying said:
ok, but I am confused with whether the force of the train is equal to the force of the train on one car?

You don't need to bother about the force on one car. The train is made up of 25 cars, the mass of the train is 25 * mass of one car.
 
So then its basically this:

25 trains * 6.8e4 kg/train * .20 m/s^2 - 250 * 12.22222222m/s = ma

336944.444 = ma

is this the answer? I've entered this into webassign and it says its wrong.
 
25 cars means 25 times the drag force too, right?
 
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