Finding free electron gas Green function in Fourier space

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The discussion focuses on deriving the Green function for a free electron gas in Fourier space, referencing Fetter's 1971 work. The user expresses confusion about the exponential terms in the Green function, particularly the sign in the time-dependent exponential and how to handle the field operator's sandwiching. There is mention of the step function's role in the two-time region and its relation to the filled Fermi sea. The user seeks clarification on these points, emphasizing the importance of understanding the ground state at zero temperature. Overall, the conversation highlights the complexities involved in this quantum mechanics topic.
kakaho345
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Homework Statement
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Relevant Equations
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As in title:
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Plugging in the definition is straight forward, I am too lazy to type, I will just quote the book Fetter 1971:
1681350111348.png

1681350169049.png

1681350186563.png

1681350198430.png

Up to here everything is very straight forward, in particular, since we are working on free electron gas, ##E=\hbar \omega##

However, I have no idea how to arrive here:
1681350443696.png

I understand that ##e^{ik\cdot(x-x')}## is from terms like ##\psi=e^{ikx}c##, however, the term ##e^{-i\omega_k(t-t')}## the sign doesn't look right to me for the two time region should have different signs in the exponential. Also, I don't know how to deal with the exponential sandwiched between the field operator. The step function in time is from the two pieces of time regions, but I am not sure on the step function in k. I may be from the filled Fermi sea.

I understand this is a very simple question. However, I have been sitting whole day dealing with this. Any help will be appreciated.
 
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You simply have to think about, how the ground state looks like! Note that at ##T=0## the system is in a pure state of lowest possible energy under the given constraints. First think what is the constraint here!
 
I want to find the solution to the integral ##\theta = \int_0^{\theta}\frac{du}{\sqrt{(c-u^2 +2u^3)}}## I can see that ##\frac{d^2u}{d\theta^2} = A +Bu+Cu^2## is a Weierstrass elliptic function, which can be generated from ##\Large(\normalsize\frac{du}{d\theta}\Large)\normalsize^2 = c-u^2 +2u^3## (A = 0, B=-1, C=3) So does this make my integral an elliptic integral? I haven't been able to find a table of integrals anywhere which contains an integral of this form so I'm a bit stuck. TerryW

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