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davydany
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Homework Statement
A bi-concave lens (n=2) has radii of 15cm and 25cm, and an axial thickness of 6-cm. Use the thin-lens equation to see how far off it is in determining the final image location.
Homework Equations
n1/so + n2/si = (n2 – n1)/R;
(n-1)(1/R1 – 1/R2) = 1/f
The Attempt at a Solution
I got the focal length of the lens to be 28.846 using the 2nd equation above.
(2-1)[1/15 - 1/25 + ((2-1)*6) / (2*15*25))] = 28.846
I found h1 and h2 to be -3.46 and -5.77, respectively.
I realize that So = 10cm + h1 = 10 + 3.46 = 13.46
I plugged this into the Len's Maker's Equation (1/so + 1/si = 1/f) and found that si = 25.24.
I had a couple of questions with this:
- Do thick concave lens have first and second principle points (h1 and h2)?
- The axial thickness is 6cm. However, h2 is -5.77 and h1 is -3.46. It seems like they are crossing each other and h2 is found where h1 is supposed to be and vice versa.
- Am I approaching this correct?