Finding integrals of the product of trig functions

DrWillVKN
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Homework Statement


I've come across integrals of exponential and trig functions and I have no idea how to do them. Integration by parts doesn't really work because they just derive into either e or another trig function.

One of them is \intsin(a)*sin(b - a)da
Another is \inte(a)*sin(a)da

Homework Equations


sin(x + y) =sinx(cosy) + siny(cosx)
cos(x + y) = cosx(cosy) - sinx(siny)
sin^2(x) = (1 - cos2x)/2

The Attempt at a Solution


I've tried to use the trig identity for sin(b-a), but that just gives an extremely long sin and cos statement that doesn't help. the one with e is even more confusing. How am I supposed to manually solve them?
 
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For the second problem, let

I = \int e^{a} sin(a) da

Then integrate the right side by parts twice, and note that you get, as your integral, I. From there, just solve for I.
 
Another trick for integrating integrals like ∫exsin(x)dx is to instead do the integral ∫exeixdx =∫e(1+i)xdx as a simple exponential. Rationalize the result and note your original integral is the imaginary part. This avoids two integrations by parts and gives you the ∫excos(x)dx from the real part as a free bonus.
 
thanks for the replies, found the answers. i just didn't go far enough with the identities and integration by parts.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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