Finding Intersection Point Between Two Trigonometric Functions

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SUMMARY

The discussion focuses on finding the intersection point between the trigonometric functions y=4sin(x) and y=3cos(x) within the interval from x=0 to x=0.3π. The user initially attempts to solve for the intersection by equating the two functions, leading to the equation tan(x)=3/4. A participant clarifies that the intersection point can be expressed as x=arctan(3/4), which simplifies the area calculation between the two curves. The integral from 0 to arctan(3/4) and from arctan(3/4) to 3π/10 can be computed to find the total area enclosed.

PREREQUISITES
  • Understanding of trigonometric functions, specifically sine and cosine.
  • Knowledge of solving equations involving tangent, sine, and cosine.
  • Familiarity with definite integrals and area under curves.
  • Ability to compute arctangent values and their implications in trigonometric contexts.
NEXT STEPS
  • Learn how to compute definite integrals of trigonometric functions.
  • Study the properties of arctangent and its applications in geometry.
  • Explore numerical methods for approximating integrals when exact values are complex.
  • Practice finding intersections of other trigonometric functions analytically.
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Students studying calculus, particularly those focusing on integration and the analysis of trigonometric functions, as well as educators seeking to enhance their teaching methods in these areas.

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Homework Statement



Find the area of the region enclosed between y=4sin(x) and y=3cos(x) from x=0 to x=0.3π.

Homework Equations





The Attempt at a Solution



So I know how to do most of this question, the area i am stuck on is finding the intersection point between the two functions, since i know you must have two different areas and then add them to find the total area.

I am looking to find this intersection point without a calculator.

I tried to equate 4sinx=3cosx, changing this to 3/4=sinx/cosx, then tanx=3/4. This gets me nowhere though, can anyone help?
 
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doctordiddy said:

Homework Statement



Find the area of the region enclosed between y=4sin(x) and y=3cos(x) from x=0 to x=0.3π.

Homework Equations


The Attempt at a Solution



So I know how to do most of this question, the area i am stuck on is finding the intersection point between the two functions, since i know you must have two different areas and then add them to find the total area.

I am looking to find this intersection point without a calculator.

I tried to equate 4sinx=3cosx, changing this to 3/4=sinx/cosx, then tanx=3/4. This gets me nowhere though, can anyone help?

I'm not sure why you are trying to pull this off without a calculator, but if tan(x)=3/4 then x=arctan(3/4). So you've found the intersection. The integral from 0 to arctan(3/4) actually comes out pretty neatly. Doing the integral from arctan(3/4) to 3*pi/10 can also be done if you are ok with things like cos(3*pi/10) and sin(3*pi/10) appearing in the final answer. At that point I'd use a calculator if you want an actual number.
 
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