Finding Iz and Is for VZ = 7.2V with RL = 10Ω

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To find the zener current (Iz) and source current (Is) for a zener voltage (VZ) of 7.2V with a load resistance (RL) of 10Ω, the calculations involve determining the resistance (RS) needed to maintain a regulated load voltage (VL) of 7.2V while accounting for a ±10% variation in the input voltage (Vin) of 12V. The zener current must remain above 77mA at the lowest input voltage, which is 10.8V. The load current (IL) can be calculated using IL = VZ/RL, and Is is derived from Is = Iz + IL. The resistance RS can then be calculated with the formula RS = (Vin - VZ)/Is. A schematic should be redrawn for Vin = 10.8V, marking all known parameters for clarity.
go2255
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I don't know how can i find the Iz and Is.

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The zener voltage VZ = 7.2V, with the condition that the zener current 77mA ≤ iZ ≤ 1A
load resistance RL = 10Ω.
What is resistance RS when load voltage VL is regulated to 7.2V while the input voltage Vin varies by ±10% from its nominal value of 12V. Also check that the zener current iZ is larger than 77mA at lowest input voltage Vin .
 
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Redraw the circuit for Vin = 12V - 10%, this time marking on every parameter you know. Post that labelled schematic.
 
Is this HW?
IL = Vz/RL
Is = Iz +IL
Rs = (Vin - Vz)/Is

George H.
 

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