Finding Length and Area of Tungsten Wire Resistor

do you think that this is as level or a2 level


  • Total voters
    1
nomnom
Messages
1
Reaction score
0

Homework Statement


the actual question is
the resitivity of tungsten metal is 4.9x10to the power of -6 Ωcm. choose appropriate values for length and cross-sectional area for a home made wire resistor of resitstance 20Ω

Homework Equations



r=pl/a
r-resistance
a-cross sectional area in m squared
l- length of wire in meters
p is resistivity of the material in ohm(meters)

The Attempt at a Solution


i don't even know wher to start all i know is that i need to find L and A but i only know p's value, please help,

 
Physics news on Phys.org


Hello, and welcome to PF. I can't answer the poll because I don't know what it is asking. I don't, for future reference, think this problem belongs in "advanced physics."

The reason you can't "solve" this problem is because you are supposed to come up with the values yourself. You could look up the standard gauges of wire (most people use 16-26awg at the very most/least) to get a range of possible area, and from there solve for length..
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top