Finding limits of 2 varible functions

  • Thread starter Thread starter tnutty
  • Start date Start date
  • Tags Tags
    Functions Limits
tnutty
Messages
324
Reaction score
1

Homework Statement




Find the limit, if exist, otherwise show why it doesn't;

F(x,y) = R;

where R =

x^2 + y^2
------------------------
sqrt( x^2 + y^2 + 1) - 1


Attempt :

|R| = R

Since I know that |x| <= sqrt(x^2) <= sqrt(x^2 + y^2 + 1) = J

R <= J^2 + J^2 / (J + 1) = 2*J^2 / (J + 1)

Stuck here.

Also does the methods of 1 variable function to find limits, such as l'hopital rule apply to 2 variable? I assume not, since the book has not mentioned it.
 
Physics news on Phys.org
i assume it is at the limit at the point (0,0) you're trying to investigate?
 
Suggestion: Go back to the beginning and rationalize the denominator.
 
Billy Bob said:
Suggestion: Go back to the beginning and rationalize the denominator.

Perfect. Should have seen that. Thank you.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top