Finding Maclaurin & Laurent Series for f(z)

bondi97
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Homework Statement



f(z) = (z + 2)/(z - 2)

a) Find the Maclaurin Series for f on the doman |z| < 2.

b) Find the Laurent Series for f centered at z0 = 0 on domain 2 < |Z| < inf.


Homework Equations




The Attempt at a Solution



I'm having a hard time figuring out how (z + 2)/(z - 2) = 1 + (4/(z-2)) = 1 - (2/(1 - (z/2)).

I tried referring to a geometric series, but I don't think I have the right approach.
 
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hmmmm... been a while but how about
\frac{z+2}{z-2} = (\frac{1/z}{1/z})\frac{z+2}{z-2} = \frac{1+2/z}{1-2/z} = (1+\frac{2}{z})\frac{1}{1-2/z}
 
or for your specific question working back
1 + \frac{4}{z-2} = \frac{z-2}{z-2} + \frac{4}{z-2} = \frac{z-2+4}{z-2} = \frac{z+2}{z-2}
is that your question?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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