Finding magnitude of the tension of a cord

  • Thread starter Thread starter schyuler2
  • Start date Start date
  • Tags Tags
    Magnitude Tension
AI Thread Summary
To find the tensions in the cords supporting a 20kg block in equilibrium, it's essential to apply the equilibrium condition where the sum of forces equals zero. The weight of the block is not zero; it is calculated as W = mg, where m is the mass and g is the acceleration due to gravity. The problem requires analyzing forces in both the x and y directions separately, considering that the upper cord has both x and y components while the horizontal cord only has a horizontal component. By setting up equations based on these components, the magnitudes of the tensions in cords A and B can be determined. Properly resolving these forces will yield the required tension values.
schyuler2
Messages
8
Reaction score
0

Homework Statement


A 20kg block is held in equilibrium by two massless cords, A, B. A is attached to the wall and B is attached to the ceiling. Find the magnitudes of the tensions of the cords.

Visual: http://i758.photobucket.com/albums/xx228/schuyler2_va/untitled.jpg?t=1260816320


Homework Equations


\Sigma Forces = m*a

Normal force = mg(cos \theta)


The Attempt at a Solution


\Sigma Forces = Tension of A + Tension of B + W + N
Tensions+Weight = ma

N = mg(cos theta)
W = 0
Tension A =?
Tension B=?

^not sure how to find the magnitudes
 
Physics news on Phys.org
schyuler2 said:

Homework Statement


A 20kg block is held in equilibrium by two massless cords, A, B. A is attached to the wall and B is attached to the ceiling. Find the magnitudes of the tensions of the cords.

Visual: http://i758.photobucket.com/albums/xx228/schuyler2_va/untitled.jpg?t=1260816320


Homework Equations


\Sigma Forces = m*a

Normal force = mg(cos \theta)


The Attempt at a Solution


\Sigma Forces = Tension of A + Tension of B + W + N
Tensions+Weight = ma

N = mg(cos theta)
W = 0
Tension A =?
Tension B=?

^not sure how to find the magnitudes
There isn't any normal force in this problem, just gravity and tension forces. Why do you say W=0 when it is given that the block has a mass of 20 kG? And since the block is in equilibrium, sum of forces is 0, because a is 0. When you sum forces, look in the x and y directions separately, or else the problem becomes vectorially overwhelming. Note that the upper cord has an x and y component of tension, while the horizontall cord has a horizontal component only.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Back
Top