Finding Mass Center of a Circular Disc with Hole & Weight

AI Thread Summary
The discussion centers on determining the center of mass of a circular disc with a hole and an additional weight attached. The center of mass is influenced by the position of the hole and the mass added at point P, which affects its location relative to the geometric center of the disc. The angle of suspension and the mass distribution play crucial roles in finding the equilibrium position. It is noted that for small values of k, the hole's impact may shift the center of mass to the left, contrary to the initial assumption. The calculation of k is essential for understanding the overall balance of the system.
Roadtrip
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Why do we take the Center of mass to be on the right side rather than on the left?
A uniform circular disc of radius 4a with a circular hole of radius 2a made in the disc.
The mass of L is m and a particle of mass km is now fixed to L at the point P. The system is now suspended from the point S and hangs freely in equilibrium. The diameter ST makes an angle a with the downward vertical through S, where tana=5/6
Find the value of K

Disc before adding weight km at point P has a mass m of coordinates (10/3,0).
https://s26.postimg.org/qczk9oc3t/image.jpg[URL]https://s26.postimg.org/lsdduqseh/image.jpg
 
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Roadtrip said:
I am having difficulty uploading a picture
You can use the "upload" button here, or upload it at some image hoster and add a link here.

I don't see images in the linked thread.
 
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The center of mass is on a line that goes from S downwards. If P is lower than Q, then it is to the right of the geometric center of the large disk. It does not have to be - for small values of k the hole is more important and the center of mass would be to the left.
 
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