- #1

Charlie_russo

- 16

- 0

Throw #1-

Distance: 52m

Time: 4.9s

Throw #2-

Distance: 65m

Time: 3.84s

So far, I have been able to figure out the horizontal velocity by using V=d/t.

#1- 52m/4.9s=10.61m/s

#2- 65m/3.84s=16.93m/s

Now, I think that in order to find the vertical velocity, I would need to first find the kongs maximum height, and then divide this by half of the time, (since at the halfway point the kong will now be traveling horizontally, and would take the same amount of time to reach the ground as a kong that is dropped from the same height). However, I am not sure on how to find the maximum height.