Finding net force, acceleration and speed.

Click For Summary
SUMMARY

The discussion focuses on calculating the net force, acceleration, and final speed of a 150 kg motorcycle that accelerates over a distance of 350 meters with an applied force of 250 N and a coefficient of kinetic friction of 0.03. The net force is determined by subtracting the frictional force from the applied force. The acceleration is calculated using Newton's second law, and the final speed is derived from the kinematic equations. The correct approach involves understanding the forces acting on the motorcycle, including gravity and friction.

PREREQUISITES
  • Newton's Second Law of Motion
  • Kinematic Equations for Linear Motion
  • Understanding of Frictional Forces
  • Basic Concepts of Force and Acceleration
NEXT STEPS
  • Calculate frictional force using the formula: Friction = coefficient of friction × normal force
  • Apply Newton's Second Law: F_net = mass × acceleration
  • Use kinematic equations to find final speed: v^2 = u^2 + 2as
  • Explore the effects of varying the coefficient of friction on acceleration and speed
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in understanding the dynamics of motion and forces acting on objects.

amable
Messages
1
Reaction score
0
A 150 kg motorcycle starts from rest and accelerates at a constant rate along a a distance of 350m. The applied force is 250 N and the coefficient of kinetic friction is 0.03

Find the net force applied to the motorcycle.
Find the acceleration of the motorcycle.
What is its speed at the end of 350 m?


I tried finding the net force by multiplying mass and gravity, but then I think I'm still wrong.
 
Physics news on Phys.org
What forces are acting on the motorcycle?

In what directions are these forces acting?
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
23
Views
3K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 41 ·
2
Replies
41
Views
4K
Replies
17
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K