Finding New Resistance of a Length of Wire

AI Thread Summary
The discussion focuses on calculating the new resistance of a length of wire that is clamped at its midpoint and stretched on one side. The original resistance is given as R, and the initial assumption was that the new resistance R' would be 1.5R based on the lengths of the wire sections. However, it is clarified that resistance is also affected by changes in the wire's cross-sectional area when stretched, which must be considered for an accurate calculation. The key takeaway is that the resistance depends on both length and cross-sectional area, leading to the conclusion that a ratio of length to cross-sectional area should be maintained. Understanding these relationships is crucial for determining the correct new resistance of the wire.
B3NR4Y
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Homework Statement


A length of wire, length l, is clamped at its midpoint. It is then stretched on the right side, with the left side unchanged, to a length of l (the right side has a length l). The original Resistance of the wire was R, what is the new resistance of the wire?

Homework Equations


R is proportional to length

The Attempt at a Solution


Using the fact that R is proportional to length (it wants R' in terms of R, so I am ignoring resistivity and such), I conclude that R' = 1.5*R, which is wrong. I got 1.5 by saying the left side is length l/2 and the rightside is length l so l+l/2 = 1.5l. So R'=1.5*R
 
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B3NR4Y said:

Homework Statement


A length of wire, length l, is clamped at its midpoint. It is then stretched on the right side, with the left side unchanged, to a length of l (the right side has a length l). The original Resistance of the wire was R, what is the new resistance of the wire?

Homework Equations


R is proportional to length

The Attempt at a Solution


Using the fact that R is proportional to length (it wants R' in terms of R, so I am ignoring resistivity and such), I conclude that R' = 1.5*R, which is wrong. I got 1.5 by saying the left side is length l/2 and the rightside is length l so l+l/2 = 1.5l. So R'=1.5*R

The resistance of the wire is proportional to length if the wire has the same diameter along it's length. When you stretch the wire the stretched part will get thinner. You need to take that into account.
 
How would I do that? Should I set up a ratio of diameter to length that should remain constant?
 
Yes. Not a simple ratio like d/l or so. Think of what does remain constant.
 
Ah, is it cross sectional area that changes? So a ratio of length to cross sectional area, since resistivity remains constant?
 
Yep
 
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