Finding Normal Components of a Plane Perpendicular to a Line in 3-Space

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Homework Help Overview

The discussion revolves around finding the components of a normal vector to a plane that is defined as being perpendicular to a given line in 3-space, represented by parametric equations.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between the normal vector and the tangent vector of the given line. There are attempts to clarify how to derive the tangent vector from the parametric equations and its connection to the normal vector of the plane.

Discussion Status

The discussion has progressed with participants sharing insights about the tangent vector and its role in determining the normal vector. Some express confusion about the conceptual understanding of these vectors, while others provide clarifications and affirmations regarding the relationships involved.

Contextual Notes

There is mention of differing instructional approaches in textbooks and from teachers regarding the concepts of tangent and normal vectors, which may contribute to the participants' confusion.

Aliboy
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Homework Statement



A plane is perpendicular to the line given by x=3+6t, Y=7+4t, and z=7-9t. What are the components of the normal to the plane

Homework Equations





The Attempt at a Solution


I don't understand what the question is asking me all I have figured out that the normal should be parallel to the perpendicular line, but I can't find the normal from the parametric.
 
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Aliboy said:

Homework Statement



A plane is perpendicular to the line given by x=3+6t, Y=7+4t, and z=7-9t. What are the components of the normal to the plane

Homework Equations





The Attempt at a Solution


I don't understand what the question is asking me all I have figured out that the normal should be parallel to the perpendicular line, but I can't find the normal from the parametric.

You can find the tangent vector to the parametric, right? What is it? Then sure, that should be parallel to the normal. Do you want a unit normal vector?
 
The only thing I don't understand is finding the tangent vector, all my book and teacher have told me is how to find the vector orthogonal to the plane.
 
Aliboy said:
The only thing I don't understand is finding the tangent vector, all my book and teacher have told me is how to find the vector orthogonal to the plane.

The tangent vector to the parametric curve (x(t),y(t),z(t)) is the derivative with respect to t of that. It's (x'(t),y'(t),z'(t)). What is that?
 
So 6,4,-9?
So the answer would be <6,4,-9>
 
Aliboy said:
So 6,4,-9?
So the answer would be <6,4-9>

That's a normal vector to your plane alright. Any multiple of that is also a normal, yes? Do they want any specific one? That's why I asked if you want a 'unit normal'.
 
I guess that should do I just don't understand the conceptual behind it.
 
Aliboy said:
I guess that should do I just don't understand the conceptual behind it.

When you said, "I have figured out that the normal should be parallel to the perpendicular line" then that pretty much sums it up. Finding a vector tangent to the perpendicular line will then give you a normal. Just as you did.
 
Thank you very much it actually makes sense now.
 
  • #10
Part of your problem is shown here:
Aliboy said:
The only thing I don't understand is finding the tangent vector, all my book and teacher have told me is how to find the vector orthogonal to the plane.

A plane doesn't have "the tangent vector". Every line in the plane gives a tangent vector. A plane is completely determined by a single point and a vector normal to the plane.
 

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