Finding Mass in SHM with Known Spring Constant and Velocity

AI Thread Summary
To find the mass of a block in simple harmonic motion (SHM) attached to a spring with a spring constant of 9.00 N/m, the block's velocity is measured at +30.0 cm/s when it is halfway between its equilibrium and maximum displacement. The correct approach involves using the relationship between angular frequency (ω), mass, and velocity. By applying the circular motion method and considering the position of the block, the mass is calculated to be 0.75 kg. Understanding the connection between velocity and mass in SHM is crucial for solving similar problems.
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Homework Statement



A block of unknown mass is attached to a spring with a spring constant 9.00 N/m and
undergoes simple harmonic motion, along the x axis, with an amplitude of 10.0 cm. When the
mass is halfway between its equilibrium position and its maximum positive displacement, its
velocity is measured to be +30.0 cm/s. Calculate
(a) the mass of the block,

Homework Equations



??

The Attempt at a Solution



I tried using the x= A cos (ωt +∅) but i can't figure it out without time. HELP?? I know the answer is suposed to be m= 0.750kg but i don't understand how to get there.
 
Physics news on Phys.org
What is cos(ωt +∅) when the mass is halfway between its equilibrium position and its maximum positive displacement?

What is the formula for velocity as function of t?
How is ω related to mass?

ehild
 
Since OP not interested, i find the problem interesting since i just started on SHM.

Using circular motion method.
Since position is halfway between its equilibrium position and its maximum positive displacement,
θ=60°
VmaxCos(90-θ)=0.3 m/s
Vmax=0.3x 2/√3

F=mv2/r
m=0.9 x 0.1 x 3/(0.36)
m=0.75 kg
 
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