Finding Points of Parallel Tangent Plane for z=(x^2)(e^y)

nirali35
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Homework Statement


Find the points on the graph of z=(x^2)(e^y) at which the tangent plane is parallel to 5x-2y-.5z=0


Homework Equations


An equation of the tangent plane to z=f(x,y) at (a,b) is:
z = f(a,b) + fx(a,b)(x-a) + fy(a,b)(y-b)


The Attempt at a Solution


Partial derivatives of function f(x,y)
fx(x,y) = 2xe^y => fx(a,b) = 2ae^b
fy(x,y) = (x^2)(e^y) => fy(a,b) = (a^2)(e^b)
 
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ideas from here? you could check when the plane normal vectors are parallel, or alternatively check when the directions of both the partial derivatives are perpindicular to the plane normal

you can also do this with graidents, but it amounts to a similar thing
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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