Finding Potential (Spherical coordinates )

hadez
Messages
2
Reaction score
0
1. . An electric dipole located at the origin in free space has a moment p = 3ax −2ay +az nC·m. Find V at r = 2.5, θ =30◦, φ =40◦.
I find it difficult to solve when its in spherical co-ordinates.2.Relevent Eq
V =P.(r-r')/( 4∏ε|r−r'|2)(|r-r'|)I am confused how to find a unit vector on spherical co-ordinate. ie |r-r'|This que is from william Hayt and page no 100.
 
Physics news on Phys.org
Thanks for the reply,but my que
1)how to find unit vector in a spherical coordinate system?
2) dipole p is in rectangular coordinate system and distancw vector is in spherical coordinate system.How do i multiply both with a dot product.?
Haunts me.
I spent a whole day and and went mad with vectors buzzin in my brain. I am preparing for an test this fundas are essential.please look into this
 
You can express the observation point for V in cartesian coordinates, then use just the cartesian coordinartes. The observation point is totally defined for you in spherical terms.

V = kp*r/r3

where r is the vector from the origin to the point of observation, and r its magnitude.

So you need to figure out how to express this potential in terms of your cartesian coordinate system, then do the dot-product with the dipole moment expression.

Don't try to do a dot-product in a spherical system. You have to translate to cartesian first.
 
Last edited:
hadez said:
1. . An electric dipole located at the origin in free space has a moment p = 3ax −2ay +az nC·m.


Should say p = 3a i - 2a j + a k,
ijk unit vectors
 
rude man said:
Should say p = 3a i - 2a j + a k,
ijk unit vectors

yes and do the dot product and expand using ##V = \frac{\vec{p} . \vec r}{4 \pi \epsilon_0 r^3}##

And for a dipole centrered at origin along z-axis for example, what can you say about azimuth dependence? Does the potential depend on ##\phi##?
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top