Finding Power Series Representation for arctan(x): Help Needed!

AI Thread Summary
To find the power series representation for arctan(x), start with the integral of 1/(1 + x^2). Differentiating this function multiple times and evaluating at x = 0 can help derive the series. The discussion emphasizes the importance of focusing on the right-hand side to obtain the series for the left-hand side. It is suggested that one can integrate term by term after obtaining the power series for 1/(1 + x^2). Understanding these steps is crucial for successfully finding the power series representation.
teng125
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may i know how to solve this ques:find the power series representation for arctan (x)

i know that arctan (x) = integ 1/(1 + x^2) but then from here i don't know how to continue.
pls help...
 
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It seems to me if you're looking for the power series of the thing on the left hand side, then you might want to try looking for the power series of the thing on the right hand side.
 
ya I'm looking for the thing on the left hand side...pls help
 
Take the thing on the right, and differentiate it a few times, and let x = 0 each time.

f(x) = f(0) + xf'(0) + \frac{x^2}{2!}f''(0) + ...

Where f'(0) represents the derivative at x = 0. f''(0) is the second derivative etc. This will give a power series, then you can integrate term by term for the inverse tan function.
 
One doesn't need to know any calculus at all to find the power series for 1/(1+x^2).


ya I'm looking for the thing on the left hand side...pls help
I gave you a big hint -- have you not tried to do anything with it?
 
teng125 said:
ya I'm looking for the thing on the left hand side...pls help

Go back and read Hurkyl's reply again!
Hurkyl said:
It seems to me if you're looking for the power series of the thing on the left hand side, then you might want to try looking for the power series of the thing on the right hand side.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks

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