Finding probability of two numbers which satisfies an inequality

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Homework Statement



Two numbers x and y are selected from a closed interval [0,4]. To find the probability that the two numbers satisfies the condition that y^{2}\leq x.


2. The attempt at a solution

Don't have any idea
 
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Draw a graph. First draw the parabola representing the function x= y^2, then draw the four line segments x= 0, y= 0, x= 4, y= 4 making a square, with vertices (0, 0), (16, 0), (16, 16), and (0, 16), and having the graph x= y^2, which is the same as y= x^{1/2}, crossing the square from (0, 0) to (4, 2). The set of points such that y^2\le x with x and y from [0, 4] is the set of point below that graph. Assuming all values of x and y between 0 and 4 are "equally likely, then all points in the square are "equally likely" and the probability a point is below the parabola is the ratio of the area under the parabola to the area of the square. Find that area by integrating x^{1/2} from x= 0 to x= 4 and then divide by the area of the square, 16.
 
Gotcha..thanks for the help
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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