Finding Real and Complex Zeroes of Polynomials

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Look up remainder and factor theorem
 
Also, look up the "rational root theorem": Any rational root of a_nx^n+ a_{n-1}x^{n-1}+ \cdot\cdot\cdot + a_1x+ a_0= 0 must have denominator the divides a_n and denominator that divides a_0. Here, a_3= 1 and a_0= 4 so there aren't too many possibilities.
 
No dice: except for the second equation, where you can pick out one "zero" right away, the candidates from the Rational Zeroes Theorem don't work here... (A graph of each suggests that those real zeroes that do exist appear to be resolutely irrational.)

What course is this for? I ask because these don't seem to be the sort of polynomials that factor nicely for an elementary course in algebra and functions. Are you allowed to use numerical methods? You might want to use the Intermediate Value Theorem to search for regions where the real zeroes exist and then use something like the Newton-Raphson method to home in on those real zeroes.

Are you also to find complex zeroes? It looks like you can extract the second real zero to solve the remaining quadratic equation. The situation with the first one looks like you may have a remaining quartic with four complex zeroes (the result from Descartes' Rule of Signs hints at this). Is there something we're supposed to notice about the coefficients that will help find those?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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