Finding resonance frequency of a hanging mass on a spring

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SUMMARY

The discussion centers on calculating the resonance frequency of a hanging mass on a spring, specifically addressing the relationship between angular frequency and frequency. Participants clarify that the equation kx=mg represents the equilibrium condition of the spring, where k is the spring constant, x is the displacement, m is the mass, and g is the acceleration due to gravity. This relationship is crucial for deriving the expression for frequency, which is defined in both radians per second and revolutions per second.

PREREQUISITES
  • Understanding of Hooke's Law and spring constants (k)
  • Knowledge of angular frequency and its relationship to frequency
  • Basic principles of equilibrium in mechanical systems
  • Familiarity with the concepts of mass (m) and gravitational acceleration (g)
NEXT STEPS
  • Study the derivation of frequency from angular frequency in harmonic motion
  • Explore the implications of Hooke's Law in dynamic systems
  • Research the effects of mass and spring constant on resonance frequency
  • Learn about the applications of resonance frequency in engineering and physics
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in the dynamics of oscillatory systems and resonance phenomena.

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Why did they calculate angular frequency if the question asked for frequency?

Also why is kx=mg? Wouldn't that mean the spring is at equilibrium?
 

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You can express frequency as rad/sec or rev/sec.

Also why is kx=mg? Wouldn't that mean the spring is at equilibrium?
In this case the spring is at equilibrium but this relationship allows you to get an expression for k/m and this is needed to get the frequency.
 

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