Finding roots of this trig eqn

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SUMMARY

The discussion centers on solving the trigonometric equation [sin(x)] + [√2 cos(x)] = -3 for x in the interval [0, 2π], where [.] denotes the greatest integer function. The participants analyze potential solutions, concluding that x must belong to either the interval (5π/4, 2π) or [π, 5π/4]. They explore the feasibility of finding solutions through substitution and inquire about alternative methods to solve the equation without exhaustive checking.

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Homework Statement


If [sinx]+[√2 cosx]=-3, x belongs to [0,2∏] (where [.] denotes the greatest integer function) then x belongs to
1)[5∏/4,2∏]
2)(5∏/4,2∏)
3)(∏,5∏/4)
4)[∏,5∏/4]

The Attempt at a Solution



If I put x=5∏/4, LHS=-2 which does not satisfy. 2∏ and ∏ also does not satisfy.So the answer must be either 2) or 3). Is there any better way other than putting the values one by one and checking?
 
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utkarshakash said:

Homework Statement


If [sinx]+[√2 cosx]=-3, x belongs to [0,2∏] (where [.] denotes the greatest integer function) then x belongs to
1)[5∏/4,2∏]
2)(5∏/4,2∏)
3)(∏,5∏/4)
4)[∏,5∏/4]

The Attempt at a Solution



If I put x=5∏/4, LHS=-2 which does not satisfy. 2∏ and ∏ also does not satisfy.So the answer must be either 2) or 3). Is there any better way other than putting the values one by one and checking?
What are the lowest possible values of the two terms on the left? How can they add to -3?
 
haruspex said:
What are the lowest possible values of the two terms on the left? How can they add to -3?

That was helpful. Thanks!
 

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