Finding rope tension and acceleration between two objects

AI Thread Summary
To find the tension and acceleration between two blocks connected by a cord over a frictionless pulley, free-body diagrams for each block are essential. Block A, with a mass of 4.0 kg, experiences a downward force due to gravity and an upward tension force, while block B, with a mass of 2.0 kg, has a frictional force acting against its motion on a horizontal surface. The equations derived from Newton's second law for both blocks yield two equations with two unknowns, allowing for the calculation of tension and acceleration. The correct answers for tension and acceleration are 13N and 1.6 m/s², respectively. Properly isolating the forces and applying the equations systematically is crucial for solving this type of problem.
Curtis
Messages
1
Reaction score
0

Homework Statement


"Block A has mass ma=4.0kg, and block B has mass mb=2.0kg. The coefficient of kinetic friction between block B and the horizontal plane is μk=0.50. The inclined plane is frictionless and at angle θ=30°. The pulley serves only to change the direction of the cord connecting the blocks. The cord has negligible mass. Find (a) the tension in the cord and (b) the magnitude of the acceleration of the blocks.

Rough drawing:
7qRwRH9.png


Homework Equations


FN=mgcosθ
fkkFn
T=mg+ma
FN=mg+may
-fk=max

The Attempt at a Solution


Well, the first thing I did was find the force acting on the pulley from the 4kg block, which I found to be 33.948N. Then, I found the kinetic friction force of the flat surface underneath the 2kg block, for which I got 9.8N. After this, I'm just completely stuck. Everything I've read about tension requires acceleration. Anyway, I tried both adding and subtracting the kinetic friction from the 4kg block's force, then dividing by 2kg. I checked the answer in the back of the book, which turned out to be 13N and 1.6m/s2 for (b), neither of which I reached through any combination of equations.

I figured that the tension is supposed to be found first though, given the order of the problems. I did mess around trying to find the acceleration a little, using -fk=max, but I didn't get further than that (if that even is in the right direction).

I really just had no idea what to do with this. I've read through the chapter and browsed the internet for no less than three hours trying to figure out something and my brain's to the point of feeling like jelly. Any help would be greatly appreciated, even just a push in the right direction.
 
Physics news on Phys.org
Curtis said:

Homework Statement


"Block A has mass ma=4.0kg, and block B has mass mb=2.0kg. The coefficient of kinetic friction between block B and the horizontal plane is μk=0.50. The inclined plane is frictionless and at angle θ=30°. The pulley serves only to change the direction of the cord connecting the blocks. The cord has negligible mass. Find (a) the tension in the cord and (b) the magnitude of the acceleration.

Homework Equations


FN=mgcosθ
For block A
fkkFn
For block B
T=mg+ma
where did this come from?
-fk=max
.No,

The Attempt at a Solution


Well, the first thing I did was find the force acting on the pulley from the 4kg block, which I found to be 33.948N. Then, I found the kinetic friction force of the flat surface underneath the 2kg block, for which I got 9.8N. After this, I'm just completely stuck. Everything I've read about tension requires acceleration. Anyway, I tried both adding and subtracting the kinetic friction from the 4kg block's force, then dividing by 2kg. I checked the answer in the back of the book, which turned out to be 13N and 1.6m/s2 for (b), neither of which I reached through any combination of equations.

I figured that the tension is supposed to be found first though, given the order of the problems. I did mess around trying to find the acceleration a little, using -fk=max, but I didn't get further than that (if that even is in the
You must use free body diagrams for each block when solving these problems. Isolate each block and show the forces acting on them. For block A , for example, the component of its weight acts down the plane, and the tension force acts up the plane. Write tthe equstion that comes from Newtons 2nd law. Do the same for the other block . You get 2 equations and 2 unknowns which you can solve.
.
 
What he said.
I just want to add that the first thing you do is draw a free-body diagram for each block separately. You appear to be trying to think about the interactions between components - don't.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top