Finding Tension when Mass Accelerates

  • Thread starter Thread starter allielove13
  • Start date Start date
  • Tags Tags
    Mass Tension
AI Thread Summary
To determine the tension in the cord attached to a 0.500 kg mass at a 30-degree angle, the forces acting in both the x and y directions must be analyzed. The equations for the sum of forces are established as ΣFx = Tcos30 and ΣFy = Tsin30 - Fg. The discussion raises the question of whether the mass is moving at a constant speed, implying no acceleration. Understanding these forces is crucial for calculating the tension accurately. The focus remains on applying Newton's second law to solve for the tension in the cord.
allielove13
Messages
3
Reaction score
0

Homework Statement


A mass of .500 kg is resting on the ground. Attached is a cord that makes a 30-degree angle with the horizontal. It is found that when the cord is pulled tight enough, the mass will skip along the ground without friction. How much tension is in the cord?
348m6ts.jpg


Homework Equations


F=ma?
T-Fg=ma?


The Attempt at a Solution


I have no idea how to start this..
 
Physics news on Phys.org
Start with the sum of forces in the x and y direction.
 
kellenm said:
Start with the sum of forces in the x and y direction.

So \SigmaFx=Tcos30
and \SigmaFy=Tsin30-Fg
?
 
Yeah that's right. Is this at a constant speed? Meaning no acceleration?
 

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

Monkey accelerating up and down a rope
Replies
38
Views
4K
How do I find acceleration and tension on an inclined plane
Replies
1
Views
2K
The tension in the cord in this system
Replies
7
Views
2K
Find the Tension in the cable when the lift is moving at constant speed
Replies
3
Views
1K
Perfect Inelastic collision with string tension
Replies
4
Views
6K
Newton's Second Law (Pulley Sustem)
Replies
3
Views
2K
What is the correct tension equation for a pendulum at rest?
Replies
2
Views
2K
Acceleration and Tension in a Pulley System
Replies
9
Views
6K
Two Weighted Pulleys with a Suspended Mass
Replies
3
Views
2K
Finding out the rotational speed of a mass
2
Replies
59
Views
5K

Hot Threads

Recent Insights

Back
Top