Finding the angle of 3-dimensional vectors.

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To find the angle between two 3-dimensional vectors, the scalar (dot) product is used. For vectors A and B, the dot product is calculated as A · B = |A||B|cos(θ). By determining the dot product and the magnitudes of both vectors, the angle θ can be found by taking the arccosine of the result. The example provided illustrates this method with specific vector components. This approach effectively calculates the angle between the two vectors.
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How would the angle between two vectors be found, if, for each vector, three components (i, j, k) were given?

Ex. Given that vector A = 2.0 i + 4.0 j - 7.0 k and vector B = 5.0 i - 3.0 j + 1.0 k, what is the angle between A and B?
 
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Use the definition of the scalar (dot) product.
 
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Ok.

We can find it by dot product.We know that for two vectors A and B

\vec{A} \cdot \vec{B} = AB\cos\theta

Hence find A dot B and divide it by AB. And take its arccosine and you will get your angle.
 
...dot...product?

All right. I'm pulling out some of my old Pre-Cal stuff, when I learned that. :DDD

Thank you.
 
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