# Finding the appropriate transformation to apply to an integral

## Homework Statement

Evaluate $$\int_0^1 \! \int_0^{1-x} \! \sqrt{x+y} \left(y-2x\right)^{2} \, \, \mathrm{d}y \, \mathrm{d}x.$$ by applying the appropriate transformation.

N/A

## The Attempt at a Solution

So far, the best I can come up with is u=1-x, v=x+y, which gives me $$\int_0^1 \! \int_0^u \! \sqrt{v} \left(v-3-3u\right)^{2} \, \, \mathrm{d}v \, \mathrm{d}u.$$.

I know how to evaluate it after applying the transformation. As far as I can tell, one of the transformations should be 1-x to deal with the limit, and the other should be x+y to deal with the square root. I was wondering if there was a better way to do the transformation, though, since it still seems like it might be somewhat painful to integrate.

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