Finding the area of a circle using integration

satxer
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Let's say I have the equation for a circle but don't know how to calculate its radius. How could I use integration to find its area?
 
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satxer said:
Let's say I have the equation for a circle but don't know how to calculate its radius. How could I use integration to find its area?

You can always get the radius from circle equations !

However, all circle equations are integrated by trigonometric substitution
and it can also be done by integration by parts but that is a bit tricky!
 
The area of a circle is a equal to the area of two half-circle.

The equation of a half-circle (assuming (y-b) is always positive and that you don't understand that r is the radius):

\left(x-a\right)^2+\left(y-b\right)^2=r^2

So the area of a circle is equal to: 2\int_{-r-a}^{r-a}y_{(x)}dx

That's a complicated way, but I guess it can be done.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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