Finding the charge and initial position, electric potential problem.

AI Thread Summary
The electric potential at a distance r from a point charge q is given as 2.40×10^4 V, and at 1 meter farther, it is 6500 V. Using the equation V=kq/r, the charge q is calculated to be 7.230 x 10^-7 C. Subsequently, the distance r is determined to be 0.27 m using the same equation. The calculations appear correct, and the discussion concludes with a prompt for further questions.
sukdede
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The electric potential a distance r from a point charge q is 2.40×104 V.
One meter farther away from the charge the potential is 6500 V.


Homework Equations


V=kq/r


The Attempt at a Solution


6500 = 8.99x10^9 (q) / 1m
q = 7.230 x 10^-7
then,
r= kq/v
r= 8.99x10^9 (7.230 x 10^-7) / 2.40×104
r= 0.27.
 
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your solution looks fine :) .. so what is your question ..
 
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