Finding the derivative of an unknowable inverse function

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Homework Statement



The function f(x) has an inverse function, g(x). Find g'(5).

Homework Equations



f(x) = x^5 + 2x^2 + 2x

The Attempt at a Solution



I don't see how I can possibly find the inverse of this function. So I opted to use the derivative rule for inverses.

f'(x) = 5x^4 + 4x + 25 = x^5 + 2x^2 + 2xThis doesn't help me either. I need to solve for x in the second equation and substitute that x in the derivative. In essence, I can't find x of f(x), and without that I can't find the value of f'(x), which is the reciprocal of g'(x).

Any help would be appreciated!
 
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Try a few simple values of x, you will quickly find an x where f(x)=5.
 
LCKurtz said:
Try a few simple values of x, you will quickly find an x where f(x)=5.

Oh wow. x=1. That was very foolish of me! Thank you for your time man.
 
The answer is g'(5)=1/11 . If anyone is curious.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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