aximwolf
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9. [1pt]
As shown in the figure above, a ball of mass 0.480 g and positive charge q =32.7microC is suspended on a string of negligible mass in a uniform electric field. We observe that the ball hangs at an angle of theta=15.0o from the vertical. What is the magnitude of the electric field?
Fx= Fe - Tsin(theta)= 0
Fy= Tcos(theta) = 0
Tsin(theta)/Tcos(theta) = Fe\mg
Than E= Fe/q
So Tan(theta)mg = Fe/q = E
I got (Tan(15)*.480*9.8)/32.7e-6= 3.9 e 4
Where did I go wrong?
As shown in the figure above, a ball of mass 0.480 g and positive charge q =32.7microC is suspended on a string of negligible mass in a uniform electric field. We observe that the ball hangs at an angle of theta=15.0o from the vertical. What is the magnitude of the electric field?
Fx= Fe - Tsin(theta)= 0
Fy= Tcos(theta) = 0
Tsin(theta)/Tcos(theta) = Fe\mg
Than E= Fe/q
So Tan(theta)mg = Fe/q = E
I got (Tan(15)*.480*9.8)/32.7e-6= 3.9 e 4
Where did I go wrong?