Finding the E-field of a mass hanging from a string

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SUMMARY

The discussion focuses on calculating the magnitude of the electric field (E) acting on a ball with a mass of 0.480 g and a charge of 32.7 microCoulombs, which hangs at an angle of 15.0 degrees from the vertical. The participant used the equations of equilibrium to derive the electric field, concluding that E equals approximately 3.9 x 10^4 N/C. The participant initially miscalculated due to unit confusion regarding mass. The discussion was appropriately redirected to the Introductory Physics Forum for better context.

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9. [1pt]
prob04_ball_in_field.gif


As shown in the figure above, a ball of mass 0.480 g and positive charge q =32.7microC is suspended on a string of negligible mass in a uniform electric field. We observe that the ball hangs at an angle of theta=15.0o from the vertical. What is the magnitude of the electric field?

Fx= Fe - Tsin(theta)= 0
Fy= Tcos(theta) = 0

Tsin(theta)/Tcos(theta) = Fe\mg

Than E= Fe/q

So Tan(theta)mg = Fe/q = E

I got (Tan(15)*.480*9.8)/32.7e-6= 3.9 e 4
Where did I go wrong?
 
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Note the units in which the mass was specified.

EDIT: Note also that since this is a homework problem, it should have been posted in one of the homework forums, in particular the Introductory Physics Forum.

EDIT by mentor: this thread has been moved to the appropriate location.
 
Last edited by a moderator:
Its right! Thank you for responding so fast!
 

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