Finding the Electric Potential at a Point Due to Multiple Charges

AI Thread Summary
The discussion revolves around calculating the electric potential at the origin due to multiple charges placed at specified coordinates. The initial calculation for the potential was performed using the formula Vo=k(q1/r1+q2/r2+q3/r3), leading to a potential of 5.93 x 10^4 V. However, there was confusion regarding the distance calculation for one of the charges, where the vector magnitude was incorrectly summed. The correct answer for the electric potential at the origin due to the charges is -1.04 Joules. The thread highlights the importance of accurately determining distances in vector form when calculating electric potential.
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Homework Statement


A charge of +21.9 micro-Coulombs is placed at x=-3.3 m, y=0 m, a charge of -8.5 micro-Coulombs is placed at x=0 m, y=+3.8 m, and a charge of +15.6 micro-Coulombs is placed at x=+3.3 m, y=+3.8 m. If a charge of -15.4 micro-Coulombs is placed at origin, what is electrical potential of this charge in Joules? Answer is -1.04.


Homework Equations


\DeltaU=Uf-Ui


The Attempt at a Solution


Vo=k(q1/r1+q2/r2+q3/r3)=(8.99 x 109Nm2/C2)(21.9 x 10-6C/3.3m+-8.5 x 10-6C/3.8m+15.6 x 10-6C/7.1m)=5.93 x 104V
Uf=q4Vo
q4Vo-0=(-15.4 x 10-6C)(5.93 x 104V)
 
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hi eesteeestep! :wink:
eestep said:
… and a charge of +15.6 micro-Coulombs is placed at x=+3.3 m, y=+3.8 m

… =(8.99 x 109Nm2/C2)(… +15.6 x 10-6C/7.1m)

no, you've added 3.8 to 3.3 to get 7.1 :frown:

(3.3,3.8) is a vector

its magnitude is … ? :smile:
 
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