Finding the Final Temperature of Hot Coffee in a Cold Cup

AI Thread Summary
To find the final temperature of hot coffee poured into a cold cup, the heat balance equation is used, where the heat lost by the coffee equals the heat gained by the cup. The equation involves the specific heat capacities of both substances, with the coffee cooling from 75.0 °C and the cup warming from 24.0 °C. The correct formula is (mass coffee)(Temp coffee - Tf)(4.18 J/g°C) = (mass glass)(Tf - temp glass)(0.840 J/g°C). Solving this equation yields a final temperature of approximately 63.57 °C. This process illustrates the principle of thermal equilibrium with no heat loss to the surroundings.
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Homework Statement


(c11p34) You pour 160.0 g of hot coffee at 75.0 oC into a 230.0- g glass cup at 24.0 oC. If they come to thermal equilibrium quickly, what is the final temperature (in oC, enter deg in asnwer box)? Assume no heat is lost to the surroundings.

Homework Equations


(I don't even know, I've seen so many.)

The Attempt at a Solution


I've attempted this problem a couple times with different formulas, but none have worked.
Can someone just tell me what equation to use, please?
 
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Suppose the final temperature is Tf. Then the coffee has cooled off to that temperature and the cup has heated up. They tell you no heat is lost, so apparently it's to do with heat. Where did the heat from the coffee go and where did the heat for the cup come from ?
 
Thank you for replying! I actually tried another equation and found the correct answer:
(mass coffee)(Temp coffee-Tf)(4.18 J/gC)=(mass glass)(Tf-temp glass)(0.840 J/gC)
(160)(75-Tf)(4.18)=(230)(Tf-24)(0.840)
Tf=63.57 deg
 
It's what we call a heat balance. Heat given off = heat taken up. And you did well to include the cp.
 
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