Finding the force (complicated)?

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To find the third force F3 acting on an object with a mass of 6.70 kg and given accelerations, the net force must be calculated using F=ma. The known forces are F1 = (2.71 N)x and F2 = (-1.55 N)x + (2.05 N)y. The acceleration components indicate the need to break down the forces into their respective x and y components. The discussion emphasizes that gravitational force should not be included since the problem specifies only three forces are acting on the object. The solution involves determining the net forces in both x and y directions to solve for F3.
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Homework Statement


An object of mass m = 6.70 kg has an acceleration a = (1.17 m/s2)x + (-0.664 m/s2)y. Three forces act on this object: F1, F2, and F3. Given that F1 = (2.71 N)x and F2 = (-1.55 N)x + (2.05 N)y, find F3.
( N)x + ( N)y


Homework Equations



I'll be honest, i have no clue. i know F=ma but have absolutely no clue since there are 3 forces and the x's and y's
 
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you need to break up all the forces into x and y components. (including mg, normal force) find the net force x and y and use F=ma to find the missing x and y, then add these forces together, (its not just x+y) and that it!
 
Yes, add the forces but I see no reason to assume that "surface of the Earth gravitation" should be included. The problem says specifically that there are three forces.
 
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