Finding the Image of a Vector under a Linear Transformation

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SUMMARY

The discussion focuses on finding the image of a vector under a linear transformation defined by L: R^3 -> R^3, where L(i) = [1, 2, -1], L(j) = [1, 0, 2], and L(k) = [1, 1, 3]. To find L([2, -1, 3]), the correct approach involves constructing a matrix representation of L using the given vectors as columns and applying it to the vector [2, -1, 3]. The transformation will yield a vector, not a single number, confirming that the output of L(v) is indeed a vector based on the linear combination of the basis vectors.

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  • Understanding of linear transformations in R^3
  • Familiarity with matrix representation of linear operators
  • Knowledge of vector addition and scalar multiplication
  • Basic proficiency in solving linear equations
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  • Study the construction of matrix representations for linear transformations
  • Learn how to perform matrix multiplication with vectors
  • Explore the concept of basis vectors and their role in linear transformations
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Students studying linear algebra, educators teaching vector transformations, and anyone interested in understanding the application of linear transformations in R^3.

superdave
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Homework Statement



Let L: R^3 -> R^3 be a linear transformation such that

L(i) = [1 2 -1], L(j) = [1 0 2] and L(k) = [1 1 3].

Find L([ 2 -1 3)].

All the numbers in [ ] should be vertical, but I don't know how to set that up.

Homework Equations





The Attempt at a Solution



I'm not sure how to even approach this. I've tried looking at examples in the text and they aren't clear.

I would think that you make a matrix L with the three columns i j k as above. and x = [2 -1 3] and just calculate Lx=b to find b.

But a similar problem in the text has a single number answer. I would've guessed that it gives a vector.
 
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You know how the transformation acts on the basis {i, j, k}. Let v be any vector, then v = αi + βj + γk. Then L(v) = αL(i) + βL(j) + γL(k).

The vectors L(i), L(j) and L(k) are the columns of the matrix representation of the operator L.
 
superdave said:
But a similar problem in the text has a single number answer. I would've guessed that it gives a vector.

You should get a vector here. Maybe you should post the similar problem and we can help you figure out what the difference is?
 

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