Finding the intersection of subspaces, and addition of subspaces

minitejpar
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Heres the question:
Let {u,v,w} be a linearly independent set of vectors of R^4. Let E = span{u,2v} and F=span{w,v}. Find EnF and E + F.


i really have no idea other than i guess if 1/2u=w and v=v, then the EnF can be defined by that, but I'm not sure if that is right! :(
 
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if u & v are linearly independent, what does span{u,v} represent?

now does span{u,2v} contain v?
 
span{u,v} represents all the combinations of u and v. (at least that's what i understand).

and yes, span(u,2v) does contain v, and so can i multiply 2v by 1/2? and then have span{u,v} instead of span{u,2v}?

if this is the case, then how do i find the intersect if F=span{w,v} seeing as w is not u..?
 
minitejpar said:
span{u,v} represents all the combinations of u and v. (at least that's what i understand).
Can you be a bit more specific as to what you mean by "combination"?
and yes, span(u,2v) does contain v, and so can i multiply 2v by 1/2? and then have span{u,v} instead of span{u,2v}?

if this is the case, then how do i find the intersect if F=span{w,v} seeing as w is not u..?
When a vector x is in E ∩ F, that means x∈E and x∈F. So you're looking for all vectors that can be expressed as a combination of u and 2v (so that it's in E) and a combination of w and v (so that it's in F). So again, it depends on what exactly you mean by "combination."
 
minitejpar said:
span{u,v} represents all the combinations of u and v. (at least that's what i understand).
span{u,v} = the set containing all linear combinations of u & v, so any vector w with:
w = a.u + b.v
for any real scalars a,b

think of u & v as vectors, what does span{u,v} represent geometrically?

note that
0 = 0.u + 0.v is in span{u,v}

minitejpar said:
and yes, span(u,2v) does contain v, and so can i multiply 2v by 1/2? and then have span{u,v} instead of span{u,2v}?
so then can you show

span{u,v} = span{u,2v}
minitejpar said:
if this is the case, then how do i find the intersect if F=span{w,v} seeing as w is not u..?
 
Your very very first step should be E = span{u, 2v} = span{u, v}. This makes life easier.
 
E + F = span{u,2v) + span{w,v} = au + 2bv + cw + dv = span(u,v,w) I think. Not comepletely sure.
 
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