Finding the length of the curve

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find the curve at the point (-8,1) that gives the integrals length in the picture posted

i literally have no clue what to do. am i supposed to take the derivative of 16/y^3 and square it?
 

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billsauce said:
find the curve at the point (-8,1) that gives the integrals length in the picture posted

i literally have no clue what to do. am i supposed to take the derivative of 16/y^3 and square it?

Well, no. The 16/y^3 should be (x')^2 for one of those functions. Which one is it?
 

Thread 'Finding the nth roots of a complex number'

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