- #1

Rasmus

- 8

- 0

## Homework Statement

Find the limit (without using L'Hospital's rule)

[tex]\lim_{x\to 0} \frac{ln(1 + sin^2x)}{e^{2x} - 1}[/tex]

## Homework Equations

## The Attempt at a Solution

I tried various substitutions in order to rewrite the expression to a standard limit. Such as t = e^x, t = ln(x), t = sin(x) as well as using rewriting the trigonometric expression a few times. Since I suck I didn't get towards anything I recognized.

I'd be grateful for any help sucking slightly less :)