The problem involves determining the location of the 2nd antinode in a standing wave, given that the 4th node is at 4.10 meters. The context is related to wave mechanics, specifically standing waves and their properties.
The discussion is ongoing, with participants exploring different interpretations of the problem. Some have attempted calculations but express confusion about the results. Questions about the physical setup of the standing wave indicate a productive direction for further inquiry.
Participants note the lack of additional information about the standing wave's characteristics, which may affect the problem's interpretation. There is also mention of a sine graph related to the standing wave, suggesting a visual representation that may aid understanding.
jamcintyre1 said:Homework Statement
The 4th node of a standing wave occurs at a position of 4.10 meters. Where is the 2nd antinode?
Homework Equations
nodes occur at: x=n*(λ/2)
antinodes: x=(n+.5)*(λ/2)
The Attempt at a Solution
n=4??
4.1m=2λ→λ=2.05m
now n=2? x=(2+.5)*(λ/2)≈2.56m wrong!
x=1.54m
jamcintyre1 said:I didn't get any more info. the solution has a sin graph I think with the 2nd antinode as the 2nd max which mazes sense, so 1.5*wavelength/2. But I can't figure out why the equation won't work. Thanks for your help btw. I'll take a look at you question.