Finding the Magnitude of Force in each of two vines

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SUMMARY

The discussion focuses on calculating the tension force in two vines supporting a gorilla with a mass of 310 kg, where each vine makes a 30° angle with the vertical. The gravitational force (Fg) is calculated using the equation Fg = mg, resulting in a force of 3041.1 N. The tension in each vine (Ft) is derived from the equation 2Ft sin(60°) = Fg, leading to a final tension value of approximately 175.58 N per vine. The clarification of the angle being from vertical is confirmed as essential for accurate calculations.

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  • Understanding of basic physics concepts such as force and tension.
  • Familiarity with trigonometric functions, specifically sine.
  • Knowledge of gravitational force calculations using Fg = mg.
  • Ability to manipulate equations to isolate variables.
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This discussion is beneficial for physics students, educators, and anyone interested in understanding force analysis in static systems, particularly in scenarios involving multiple tension forces.

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Homework Statement


A gorilla is hanging from 2 vines, each with an angle of 30° from perpendicular.
Find the Magnitude of the force of tension in each vine.
Object mass is 3.10 x 10² kg

I have made an attempt at this. I have attached my handwritten notes.
Lots of feedback please.

Thank you in advance!

Homework Equations


Fg=mg
2Ft sin60=Fg

The Attempt at a Solution


m = 310 kg
g = 9.81m/s²
Fg = 310*9.81
Fg = 3041.1N
2Ft sin60 = Fg
Ft = Fg/ (2)sin60
Ft = 3041.1/ (2).866
Ft= 3041.1/ 1.732
Ft= 17.5583x 10²
 

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Scott Towers said:
A gorilla is hanging from 2 vines, each with an angle of 30° from perpendicular.

Is that 30° from vertical? If so, you're good!
 
Yes. I'm sorry. The angle is from vertical.
 

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