Finding the Magnitude of Force in each of two vines

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To find the tension in each vine supporting a gorilla weighing 310 kg, the gravitational force (Fg) is calculated as 3041.1 N using Fg = mg. The equation 2Ft sin(60°) = Fg is then used to solve for the tension (Ft) in the vines. The final calculation yields a tension of approximately 1755.83 N in each vine. Clarification confirms that the angle is indeed 30° from vertical. This analysis effectively determines the forces acting on the gorilla in equilibrium.
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Homework Statement


A gorilla is hanging from 2 vines, each with an angle of 30° from perpendicular.
Find the Magnitude of the force of tension in each vine.
Object mass is 3.10 x 10² kg

I have made an attempt at this. I have attached my handwritten notes.
Lots of feedback please.

Thank you in advance!

Homework Equations


Fg=mg
2Ft sin60=Fg

The Attempt at a Solution


m = 310 kg
g = 9.81m/s²
Fg = 310*9.81
Fg = 3041.1N
2Ft sin60 = Fg
Ft = Fg/ (2)sin60
Ft = 3041.1/ (2).866
Ft= 3041.1/ 1.732
Ft= 17.5583x 10²
 

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Scott Towers said:
A gorilla is hanging from 2 vines, each with an angle of 30° from perpendicular.

Is that 30° from vertical? If so, you're good!
 
Yes. I'm sorry. The angle is from vertical.
 
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