Finding the Normal Equation for a Curve at a Given Point

koolkris623
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Find the equation of the line normal to the curve at (0,0). (Normal lines are perpendicular to the tangent lines)

2y + sinx = xcoxy

I found the derivative to be (cosy - cosx)/ (2+ xsiny)

then the slope tangent is 0...then the slope perpendicular to it is undefined...so then is the normal equation..x=0?
 
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That looks ok to me.
 

Thread 'Finding the nth roots of a complex number'

There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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