Finding the number of revolutions

  • Thread starter Thread starter aligass2004
  • Start date Start date
  • Tags Tags
    Revolutions
AI Thread Summary
The discussion focuses on calculating the torque and the number of revolutions of a compact disk starting from rest. The torque applied to the disk is found to be approximately 1.944 x 10^-3 Nm using the formula t = I(delta w/delta t). For the number of revolutions before reaching full speed, the user initially calculated 283.453 but was advised to convert this value to radians and check the calculations for accuracy. The key equations involve angular acceleration and the relationship between angular displacement and time. Accurate calculations are essential for determining the correct number of revolutions.
aligass2004
Messages
236
Reaction score
0

Homework Statement



Starting from rest, a 12cm diameter compact disk takes 2.7s to reach its operating angular velocity of 2005rpm. Assume that the angular acceleration is constant. The disk's moment of inertia is 2.5 x 10-5 kgm^2.
a.) How much torque is applied to the disk?
b.) How many revolutions does it make before reaching full speed?

Homework Equations



t=I(alpha)

The Attempt at a Solution


For part a I used t = I(delta w/delta t). I found w by finding the frequency (33.417rev/s), and then I plugged f into w = (2pi radians)f to get 209.965. I then found torque to be 1.944 x 10-3 Nm. I am unsure of how to solve for part b.
 
Physics news on Phys.org
I tried using delta theta = wi (delta t) + 1/2(alpha)(delta time)^2. I got 283.453, but that wasn't right.
 
Divide by 2(pi) to put your answer in radians
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top