Finding the Optimal Distance for Electron Tunneling in Gold

LisaMG
Messages
1
Reaction score
0

Homework Statement


The work function (energy needed to remove an electron) of gold is 5.1 eV. Two pieces of gold (at the same potential) are separated by a distance L.

For what value of L will the transmission probability for an electron to cross from one to the other be T≈ 10-3? Assume that G = 1 in the formula for the tunneling probability.

fig14.gif
(a) L = 0.001 nm
(b) L = 0.02 nm
(c) L = 0.1 nm
(d) L = 0.3 nm
(e) L = 4 nm

Homework Equations


T= Ge^(-2KL)
K=sqrt(2m/h^2 * (U-E))

The Attempt at a Solution


I have my final tomorrow, this is a practice exam. I tried to solve for K using 5.1eV for (U-E) and then solve for L but I can't figure it out.
 
Physics news on Phys.org
LisaMG said:
I tried to solve for K using 5.1eV for (U-E) and then solve for L but I can't figure it out.
The approach is good, so unless you show your work there is no way to tell what went wrong.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top