Finding the Other Force on a Moving Particle

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A particle moving at a constant velocity of v = (3 m/s) - (4 m/s) is subject to two forces, with one force given as F1 = (4 N) + (-7 N). Since the velocity is constant, the net force acting on the particle must equal zero, implying that the forces cancel each other out. Therefore, the second force can be calculated as F2 = -F1. This leads to the conclusion that F2 must equal the negative of F1, confirming that F1 + F2 = 0. Understanding that constant velocity indicates zero acceleration is crucial in solving for the other force.
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While two forces act on it, a particle is to move at the constant velocity v = (3 m/s) - (4 m/s) . One of the forces is F1 = (4 N) + (- 7 N) . What is the other force?

i know the formula Fnet=ma and i can't use it to find mass in this case how can i find mass first so and i know that velocity is my acceleration here
 
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I assume your notation "F1 = (4 N) + (- 7 N)" is a vector component notation? I.e., 4 in the x-direction, and -7 in the y-direction?

Whatever it is, what does Newton's 2nd law tell you about the not force, if the velocity is constant?
 
if it is moving, it continues to move at constant velocity i believe so
 
Yes, but we know it is moving with a constant velocity. So? What does the sum of the forces equal?
 
i guess zero they cancel each other?
 
but i need to find a mass in order to find F2, F2 = ma - F1
 
Why do you think you need the mass? This is only about the forces. Yes, they cancel out. You know one of them. So you can find the other one.
 
F2 = ma - F1 using this formula i can find the other force how i am not that great at physics.
 
Look, F1 + F2 = 0, so F2 = -F1, right? And you are given F1.
 
  • #10
now i understand why because when constant velocity acc is 0 and when acc is zero the net force is 0 so F1+F2 =0 is this correct conclusion?
 
  • #11
Yes, that is absolutely correct.
 
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