The give force is conservative [tex]F=A(y,x,0)[/tex] where A is a constant.
The Attempt at a Solution
To find the potential function we integrate the negative of the force. Setting the potential U to be zero at the origin, we can integrate over an easy path, so I think going over to the x direction once, and then up in the y direction could work right?
So here are the two integrals(the z-direction force is zero so it's integral would be zero as well.
[tex]-A\int_0 ^x y' dx' +-A\int_0 ^y x' dy'[/tex]
If I do those integrals I get -2Axy, yet the answer is supposed to be -Axy, I'm wondering if maybe the path I'm using is wrong?